Defuse the Bomb
#cp-easy
You have a bomb to defuse, and your time is running out! Your informer will provide you with a circular array codeΒ of length of nΒ and a key k.
To decrypt the code, you must replace every number. All the numbers are replaced simultaneously.
- If
k > 0, replace theithnumber with the sum of the nextknumbers. - If
k < 0, replace theithnumber with the sum of the previousΒ -knumbers. - If
k == 0, replace theithnumber with0.
As code is circular, the next element of code[n-1] is code[0], and the previous element of code[0] is code[n-1].
Given the circular array code and an integer key k, return the decrypted code to defuse the bomb!
Example 1:
Input: code = [5,7,1,4], k = 3 Output: [12,10,16,13] Explanation: Each number is replaced by the sum of the next 3 numbers. The decrypted code is [7+1+4, 1+4+5, 4+5+7, 5+7+1]. Notice that the numbers wrap around.
Example 2:
Input: code = [1,2,3,4], k = 0 Output: [0,0,0,0] Explanation: When k is zero, the numbers are replaced by 0.
Example 3:
Input: code = [2,4,9,3], k = -2 Output: [12,5,6,13] Explanation: The decrypted code is [3+9, 2+3, 4+2, 9+4]. Notice that the numbers wrap around again. If k is negative, the sum is of the previous numbers.
class Solution:
def decrypt(self, code: list[int], k: int) -> list[int]:
N = len(code)
result = [0] * N
if k == 0:
return result
# Define initial window boundaries based on k
if k > 0:
left = 1
right = k
else:
left = N + k # If k is negative, N + k steps backward from the end
right = N - 1
# Calculate the sum for the initial window (i = 0)
current_window_sum = 0
for i in range(left, right + 1):
current_window_sum += code[i % N]
result[0] = current_window_sum
# Slide the window across the rest of the array
for i in range(1, N):
# Remove the element leaving the window
current_window_sum -= code[left % N]
# Advance boundaries circularly
left += 1
right += 1
# Add the element entering the window
current_window_sum += code[right % N]
result[i] = current_window_sum
return result